(4y-1)=(16^2+4y+1)

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Solution for (4y-1)=(16^2+4y+1) equation: 



(4y-1)=(16^2+4y+1)

We move all terms to the left:

(4y-1)-((16^2+4y+1))=0

We get rid of parentheses

4y-((16^2+4y+1))-1=0



We calculate terms in parentheses: -((16^2+4y+1)), so:

(16^2+4y+1)

We get rid of parentheses

4y+1+16^2

We add all the numbers together, and all the variables

4y+257

Back to the equation:

-(4y+257)



We get rid of parentheses

4y-4y-257-1=0

We add all the numbers together, and all the variables

-258!=0

There is no solution for this equation

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